sheila is now 15 years older than her yonger brother sanjay.ten years from now,shiela will be twice as old as sanjay.find present age of each of them.
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Let the Present age of Sanjay (in Years ) = x
Therefore , Present age of Sheila = x+15
After 10 years ,
Shielas age = x+15+10
= x+25
sanjay's age = x+10
According to question ,
x+25 = 2(x+10)
x+25 = 2x + 20
25 = 2x + 20 - x
25 = x+20
25 - 20 =x
5 =x
or x=5
Hence Present age of Sanjay = 5 years
and Present age of Shiela = x+15
= 5+15
= 20 years
Hope this helps you!!
Thank You!!
Cheers !!
Let the Present age of Sanjay (in Years ) = x
Therefore , Present age of Sheila = x+15
After 10 years ,
Shielas age = x+15+10
= x+25
sanjay's age = x+10
According to question ,
x+25 = 2(x+10)
x+25 = 2x + 20
25 = 2x + 20 - x
25 = x+20
25 - 20 =x
5 =x
or x=5
Hence Present age of Sanjay = 5 years
and Present age of Shiela = x+15
= 5+15
= 20 years
Hope this helps you!!
Thank You!!
Cheers !!
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