Question

sheila is now 15 years older than her younger brother sanjay.ten years from now,sheila will be twice as old as sanjay.find the present age?​

Answer 1

Answer:

sanjay is 5 years and sheila is 15

the equations are-

y=x+15

(y+10)=2(x+10)

Step-by-step explanation:

Answer 2

Given:

Age of Sheila and Sanjay 10 years before.

To find:

Present age of Sheila and Sanjay.

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Let the present age of Sheila= x+15

Let the present age of Sanjay= x

$after \: 10 \: years$

Sheila's age:- x+15+10=x+25

Sanjay's age:- x+10

$according \: to \: the \: question$

x+25=2(x+10)

x+25=2x+20

x-2x=20-25

-x = -5

We'll cut the negative signs here:-

x= 5 years

So present age of Sheila= 5+15= 20 years

Present age of Sanjay= 5 years

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