Question

Sheila is now 15 years older than her younger brother Sanjay . Ten years from now , Sheila will be twice as old as Sanjay . Find the present age of each of them .



please answer step by step ​

Answer 1

Answer :

    Let the Present age of Sanjay (in Years ) = x

    Therefore , Present age of Sheila = x+15

    After 10 years ,

      Shielas age =  x+15+10

                        = x+25

      sanjay's age = x+10

According to question ,

              x+25 = 2(x+10)

              x+25 = 2x + 20

            25 = 2x + 20 - x

            25 = x+20

            25 - 20 =x

            5 =x

or x=5

Hence Present age of Sanjay = 5 years

and Present age of Sheila = x+15

                                     = 5+15

                                      = 20 years

Step-by-step explanation:

Hope this will help you.

Answer 2

Answer:

Sanjay = 5years, Sheila= 20 years

Step-by-step explanation:

• let the present age of Sanjay be X and Sheila be y.
• then, y =X+15. ( at present ). (1)
• after 10 years,
• y+10 =2(X+10) (2)
• put (1) in (2)
• we get, X+15+10= 2x+20
• X=5 years
• now , put value of X in (1),
• we get, y= 20 years
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