Question

Sheila is now 15 years older than her younger brother Sanjay. Ten years from now, Sheila will be twice as old as Sanjay. Find the present age of each of them.
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Answer 1

let x=sanjay's present age

x+15=shila's present age

10 years hence:

sanjay's age=x+10

shila's age=x+15+10=x+25

x+25=2(x+10)=2x+20

x=25-20=5

x+15=20

ans:

sanjay's present age=5

shila's present age=20

Step-by-step explanation:

Answer 2

ANSWER⤵️

Let the present age of Sanjay (Sheila's brother)be x years

∴Present age of Sheila = ( x+ 15 )

Age after 10 yrs

Sheila's age = (x + 15 + 10)= (x + 25)

Sanjay's age = ( x +10)

Now,

According to the given condition,

∴ x + 25 = 2 (x +10)

∴ x+ 25 = 2x + 20

∴ 25 = 2x + 20 - x

∴ 25 = x+ 20

∴ 25 - 20 = x

∴ x = 5

Substituting The value we get;

Present age of Sanjay = 5 yrs

Present age of Sheila = x+15

= 5 + 15

= 20 yrs

STUDY WELL☺