Question

SHEILA IS NOW 15 YEARS OLDER THAN HER YOUNGER BROTHER SANJAY. TEN FROM NOW, SHEILA WILL BE YWICE AS OLD AS SANJAY. FIND THE PRESENT AGE OF EACH OF THEM

Answer 1

Let the age of Sanjay be x

Let the age of Sheila be x + 15


Ten years from now, Sheila's age = x + 15 + 10 = x + 25

Sanjay's age = x + 10


A/Q,

2(x + 10) = x + 25

2x + 20 = x + 25

2x - x = 25 - 20

x = 5


$\therefore{}$ Sanjay's age = 5 years


$\therefore{}$ Sheila's age = x + 15 = 5 + 15 = 20 years

Answer 2

Let the age of sanjay be x.

Given that Sheila is 15 years older than her younger brother sanjay.

Then, the age of sheila = x + 15.

10 years from now:

= > Age of sheila = x + 15 + 10 = x + 25.

= > Age of Sanjay = x + 10

Now,

= > x + 25 = 2(x + 10)

= > x + 25 = 2(x + 10)

= > x + 25 = 2x + 20

= > x - 2x = 20 - 25

= > x = 5.

Then,

= > x + 15

= > 5 + 15

= > 20.

Therefore, present age of Sheila = 20 years and Sanjay = 5 years.

Hope this helps!