Math, asked by shrutideore20, 9 months ago

Sheila is now 15years older than Sanjay.ten years from now ,Sheila will be twice as old as sanjay find their present age

Answers

Answered by aaa911
0

Answer:

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Answered by saniya545
5

Step-by-step explanation:

let Sanjay's age be x years.

therefore, Sheila's age = x+15 yrs

after 10 yrs,

Sanjay's age=x+10 yrs

Sheila's age=(x+15)+10 yrs

=x+25 yrs

acc. to ques.,

x+25=2(x+10)

x+25=2x+20

so,x=5

Sanjay's present age =5 yrs

Sheila's present age =15+x=20 yrs

hope it helps!

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