Question

Shekar gives
a quarter of his sweets to Ramu and the
gives 5 sweets to Raju. He has 7 sweets left how many did he have to start with​

Answer 1

Answer:

Step-by-step explanation:

let the number of sweets be z

sweets are given to ramu =  1/4 of z

sweets are given to raju = 5

the number of sweets left = 7

A/Q

z/4 + 5 + 7 = z

z + 12 = z x 4

z + 12 = 4z

now you can solve

Answer 2

Answer:

16 sweets

Step-by-step explanation:

Let's assume Shekhar had x sweets

He gives 1/4 x sweets to Raju

So now shekar has x-1/4x = 3/4 x sweets

He gives 5 sweets to raju

So he has 3/4x - 5 sweets

Now he has 7 sweets

3/4x - 5 =7

3/4 x = 12

X = 12×4/3

X= 16

He had 16 sweets to start with