Math, asked by susmitasim, 1 year ago

Shekar gives a quarter of his sweets to renu and 5 sweets to raji he has 7 sweets left how many did he have to start with

Answers

Answered by pranav071
10
Shekar was having 16 sweets in the beginning.
Answered by parasg902
39
Let the total no. of sweets with Shekar in the beginning be x.
  Sweets left with shekar = 7
   sweets he gave to raji = 5
    sweets given to renu = quarter of his sweets = 1x/4 = x/4

A.T.Q

7 + 5 + x/4 = x
12 + x/4  = x
x - x/4 = 12
4x - x / 4 = 12
3x/4 = 12
x = 12 * 4 / 3
x = 48 / 3
x = 16

Therefore , Shekar had total 16 sweets in the beginning.


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