Question

Shekhar gives a quarter of his sweets to Renu and then gives 5 sweets to raji. He has 7 sweets left. How many did he have to start with?

Answer 1

Let the total number of sweets be x

Given that, $\frac{1}{3}$ x + 5 + 7 = x

⇒ $\frac{x + 15+ 21}{3}$ = x

⇒ 36 = 3x-x

⇒36 = 2x

⇒ x= $\frac{36}{2}$

⇒ x= 18

Hence the initial number of sweets he had was 18

Answer 2

Answer:

16

Step-by-step explanation:

let the number of sweets that Shekar had at beginning be x

sweets given to Renu= x/4

sweets given to Raji=5

x-x/4-5=7

4x-x-20=28

3x-28+20

3x=48

x=48/3

x=16

So, Shekar had 16 sweets at beginning.

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