Math, asked by Rudhrapathi1234, 7 months ago

shekhar gives a quater of his sweets to renu and then gives sweets to rajji. he has 7 sweets left? how did he have to start with ​

Answers

Answered by vadu1010
0

Answer:

Let the total no. of sweets with Shekar in the beginning be x.

  Sweets left with shekar = 7

   sweets he gave to raji = 5

    sweets given to renu = quarter of his sweets = 1x/4 = x/4

A.T.Q

7 + 5 + x/4 = x

12 + x/4  = x

x - x/4 = 12

4x - x / 4 = 12

3x/4 = 12

x = 12 * 4 / 3

x = 48 / 3

x = 16

Therefore , Shekar had total 16 sweets in the beginning.

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