Question

Shell program to find second smallest number in array

Answer 1

Answer:

#! /usr/bin/bash

# ask user to enter number of elements in array

echo "Enter number of elements in array"

read n

# declare array

declare -a arr

# ask user to enter elements in array

echo "Enter elements in array"

for ((i=0;i<n;i++))

do

   read arr[i]

done

# find second smallest number in array using a loop

smallest=${arr[0]}

secondsmallest=${arr[0]}

for ((i=0;i<n;i++))

do

   if [ ${arr[i]} -lt $smallest ]

   then

       secondsmallest=$smallest

       smallest=${arr[i]}

   elif [ ${arr[i]} -lt $secondsmallest ] && [ ${arr[i]} -ne $smallest ]

   then

       secondsmallest=${arr[i]}

   fi

done

echo "Second smallest number in array is $secondsmallest"

Explanation:

The program first ask the user to enter the size of the array. Then it ask the user to enter the elements of the array.

After that a loop traversal is made to find the second smallest element.

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