Math, asked by jaiswalneha6445, 10 months ago

sher singh bought some oranges and apples. Oranges were bought at 7 for rs.50 and apples at 5 for rs.30. If sher singh spent and equal amount of money on the apples and oranges. What was the least number of fruits he bought.​

Answers

Answered by rattansingh7001
1

Answer:

rs.80

Step-by-step explanation:

Oranges were 7 bought =rs.50

Apple were 5 bought=rs. 30

if sher singh spent and

equal amount of money on

the apples and oranges =50 + 30

= rs. 80 Ans.......

Answered by FelisFelis
2

He can bought 46 fruits.

Step-by-step explanation:

Consider the provided information.

Oranges were bought at 7 for rs.50 and apples at 5 for rs.30.

First find the LCM of 50 and 30.

50 = 2×5×5

30 = 2×3×5

The LCM of 50 and 30 is 2×3×5×5 = 150

That means sher singh needs to spend Rs 150 for oranges and Rs 150 for apples.

Oranges were bought at 7 for rs.50.

7 oranges = Rs 50

7×3 oranges = Rs 50×3

21 oranges = Rs 150

Apples at 5 for rs.30.

5 Apples = Rs 30

5×5 Apples = Rs 30×5

25 Apples = Rs 150

Hence, the least number of fruits he bought:

21 oranges + 25 apples = 46 fruits

Hence, he can bought 46 fruits.

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