Question

Sher Singh jogs from A to B in a straight line for a distance of 250 m road in 1 minute and 40 seconds. he then turns around and jogs 50 m back to point C in the same straight line in 30 seconds. Calculate the average speed and velocity in jogging from:
1.) A to B
2.) A to C​

Answer 1

Total Distance covered from AB = 300m Total time taken = 2—60+30s =150s Therefore, Average speed from AB= Total Distance/ Total Time =300/150m s-1 =2ms-1 Therefore, velocity from AB= Displacement AB / Time = 300 /150ms-1 =2m s-1 Total Distance covered from AC=AB+BC =300+200m Total time taken from A to C=Time taken for AB + Time taken for BC =(2—60—30)+60s =210s Therefore, Average Speed from AC=Total Distance/Total Time =400/210m s-1 =1.904m s-1 Displacement (s) from A to C = AB €“ BC =300 €“ 100m =200 m Time (t) taken for displacement from AC=210s Therefore, velocity from AC=Displacement (s) / Time (t) =200/210m s-1 =0.952m s -1