Question

Sherin and her husband on their wedding anniversary decided to spend the time in a special school. They bought chocolates to give to children and adults working there. They gifted 2 chocolates to each child and 3 chocolates to each adult working there. They distributed a total of 60 chocolates


2. If the number of children is 15, then find the number of adults?
1 point
(i) 10
(ii) 15
(iii) 25
(iv) 20
3. Find the value of b, if x = 5, y = 0 is a solution of the equation 3x + 5y = b. *
1 point
(i) 12
(ii) 15
(iii) 14
(iv) 18
4. Which is the standard form of linear equations in two variables: y – x = 5 ? *
1 point
(i) 1.y – 1.x – 5 = 0
(ii) 1.x – 1.y + 5 = 0
(iii) 1.x + 0.y + 5 = 0
(iv) 1.x – 1.y – 5 = 0

Answer 1

Given : gifted 2 chocolates to each child and 3 chocolates to each adult

distributed a total of 60 chocolates

To Find: If the number of children is 15, then find the number of adults?

Solution:

gifted 2 chocolates to each child

Number of children = 15

Chocolates distributed to children = 2 * 15 = 30

Total chocolates = 60

Remaining chocolates = 60 - 30 = 30

Chocolates given to each adult = 3

Number of Adults = 30/3 = 10

3x + 5y = b.

x = 5 , y = 0

=> 3(5) + 5(0) = b

=> 15 = b

y – x = 5

ax + by + c = 0

=>  1.x  - 1.y + 5 = 0

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