Math, asked by 12345678901210, 10 days ago

Shikha deposited ₹2000 in a bank which pays 6% simple interest. She withdrew ₹700 at the end of the first year. What will be her balance after 3 years?​

Answers

Answered by Nobita681
1

Principal amount deposited (P) = Rs 2000

Time period (T) = 1 year

Rate of interest (R) = 6% p.a.

Interest after 1 year =

100

P×R×T

1420×6×2

= Rs 170.40

Total amount after 3 years = Rs 1420 + Rs 170.40 = Rs 1590.40 =

100

2000×6×1

= Rs 120

So, amount after 1 year = Principal amount + Interest = 2000 + 120 = Rs 2120

After 1 year , amount withdrawn = Rs 700

Principal amount left (P1) = Rs 2120 - Rs 700 = Rs 1420

Time period (T) = 2 years

Rate of interest (R) = 6% p.a.

Interest after 2 years =

100

P×R×T

=

100

1420×6×2

= Rs 170.40

Total amount after 3 years = Rs 1420 + Rs 170.40 = Rs 1590.40

Answered by Anonymous
2

Principal amount deposited (P) = Rs 2000

Time period (T) = 1 year

Rate of interest (R) = 6% p.a.

Interest after 1 year = 100P×R×T1420×6×2= Rs 170.40

Total amount after 3 years = Rs 1420 + Rs 170.40 = Rs 1590.40 = 1002000×6×1= Rs 120

So, amount after 1 year = Principal amount + Interest = 2000 + 120 = Rs 2120

After 1 year , amount withdrawn = Rs 700

Principal amount left (P1) = Rs 2120 - Rs 700 = Rs 1420

Time period (T) = 2 years

Rate of interest (R) = 6% p.a.

Interest after 2 years = 100P×R×T

= 1420/100×6×2

= Rs 170.40

Total amount after 3 years = Rs 1420 + Rs 170.40 = Rs 1590.40

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