Math, asked by payash27, 1 year ago

shikha's mother is four time as old as shikha.twenty years later,she will be twice as old as shikha will be them.find shikha's present age.

Answers

Answered by maria9
8
let shikhas age be x years
Then shikhas mother's age = 4x years

after 20 years:-
shikhas age = x + 20
mother's age = 4x + 20

ATQ
2 (x + 20) = 4x + 20
2x + 40 = 4x + 20
4x - 2x = 40-20
2x = 20
x = 10

shikhas age = 10 years
mother's age = 4(10) = 40 years
Answered by sreedhar2
3
Let the present age of shikha be = x yrs.

Then hey mother's age = 4x yrs

After 20 years their ages are

shikha = x + 20 yrs and her mother= 4x +20 yrs.

According to the problem,

2 (x + 20) = 4x + 20

2x + 40 = 4x + 20.

40 - 20 = 4x - 2x

2x = 20.

x = 20/2

x = 10.

So, present age of shikha = 10 yrs.

:))
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