Question

Shikha works in a factory. In one week she earned Rs. 390 for working 47hours, of which 7 hours were overtime. The next week she earned Rs.416 for working 50 hours, of which 8 hours were overtime. What is Shikha’s hourly earning rate?​

Answer 1

$\underline{ \large\bold { \: Given: \: }}$

• Rs. 390 for working 47hours
• Overtime: 7 hour

Next week

• Rs.416 for working 50 hours
• Overtime: 8 hour

$\underline{ \large\bold { \: To \: find: \: }}$

• Shikha’s hourly earning rate

$\underline{ \large\bold { \: Solution : \: }}$

Lets

Shikha earning be Rs x per hour

Overtime Rs is y

$\rm Condition \: 1st : \\ {:\longrightarrow \boxed{\tt{390 = 40 + 7y}}}$

$\rm Condition \: 2nd : \\ {:\longrightarrow \boxed{\tt{416 = 42 + 8y}}}$

$\: \: \: \: \: \: \: \: \: \: \tt 320x - 56y = 3120 \\ \: \: \: \: \: \: \: \: \: \: \tt 294x - 56y = 2912 \\ \: \: \: \: \: \: \: \: \: \: \: \tt \: \: \: \: \: \: \: \: \: - \: \: \: \: \: \: - \: \: \: \: \: \: \: - \\ \rm{sub} \: \: \: \: \: \: {\overline{\underline{\tt 26x - \: \: \: \: \: \: \: \: \: \: \: \: = 208}}}$

Multiplying the Equation (1) by 8 and Equation (2) by 7

$\implies \tt \: x = \frac{208}{26} \\ {\implies {\tt{\boxed{\green{ x = 8}}}}}$

Substituting the value of x in equation 1 we get,$</p><p> \tt: \implies40 \times 8 + 7y = 390 \\ \tt: \implies320 + 7y = 390 \\ \tt: \implies 7y = 390 - 320 \\ \tt: \implies 7y = 70 \\ \tt : \implies \:\frac{ \cancel{70}}{ \cancel{7}} , y = \boxed{\red{ 10}}</p><p>$

Hence,Shikha earning be Rs 8 per hour Overtime Rs is 10

Answer 2

Answer:

here is the answer

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