Shikhar secured 73,86,78 and 75 marks in four tests. What is the least Number of points she can secure in her next test if she is to have an average of 80
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Answered by
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Hey!!!!
Good Morning
__________
let the marks which Shikhar has to secure be x marks.
Number of Tests => 5(n)
Past Score => 73,86,78 and 75
Required Average = 80
Thus we know
=> Average = Sum of all observations/n
=> Sum of all observations = 73 + 86 + 78 + 75 + x
=> Sum = 312 + x
Thus Average = (312 + x)/5
=> 80 = (312 + x)/5
=> 312 + x = 400
=> x = 88
Thus Shikhar has to score 88 marks in next test to make an average of 80.
___________
Hope this helps ✌️
Good Morning
__________
let the marks which Shikhar has to secure be x marks.
Number of Tests => 5(n)
Past Score => 73,86,78 and 75
Required Average = 80
Thus we know
=> Average = Sum of all observations/n
=> Sum of all observations = 73 + 86 + 78 + 75 + x
=> Sum = 312 + x
Thus Average = (312 + x)/5
=> 80 = (312 + x)/5
=> 312 + x = 400
=> x = 88
Thus Shikhar has to score 88 marks in next test to make an average of 80.
___________
Hope this helps ✌️
Answered by
8
let the marks which Shikhar has to secure be x marks.
Number of Tests => 5(n)
Past Score => 73,86,78 and 75
Required Average = 80
Thus we know
=> Average = Sum of all observations/n
=> Sum of all observations = 73 + 86 + 78 + 75 + x
=> Sum = 312 + x
Thus Average = (312 + x)/5
=> 80 = (312 + x)/5
=> 312 + x = 400
=> x = 88
Thus Shikhar has to score 88 marks in next test to make an average of 80.
Number of Tests => 5(n)
Past Score => 73,86,78 and 75
Required Average = 80
Thus we know
=> Average = Sum of all observations/n
=> Sum of all observations = 73 + 86 + 78 + 75 + x
=> Sum = 312 + x
Thus Average = (312 + x)/5
=> 80 = (312 + x)/5
=> 312 + x = 400
=> x = 88
Thus Shikhar has to score 88 marks in next test to make an average of 80.
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