Ship A streams down north at a speed of 8kmph, ship B due West at a speed of 6kmph. The velocity of A w.r.t B is
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Given,
Ship A streams down north at a speed of 8 kmph and ship B due west at speed of 6 kmph.
To Find,
The velocity of A w.r.t B.
Solution,
The velocity of A w.r.t B will be
Vab = √(Va²+Vb²-2Va*Vbcos90°)
Vab = √(8²+6²+0) { cos 90° = 0 }
Vab = √100
Vab = 10 kmph
Now, the direction of the velocity will be
θ = tan⁻¹(Va/Vb)
θ = tan⁻¹(8/6) north of east.
Hence, the velocity of A w.r.t B will be 10 kmph in the direction tan⁻¹(8/6) north of east.
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