ship ofmass3x10 kg and initially at rest can be
pulled through a distance of 3 m by means ot a
force of 5x 10t N.The water resistance is negligible.
find the speed attained by the ship.
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Explanation:
mass of ship (m) = 3×10∧7kg [ ∧ sign indicate power ]
force (f) = 5×10∧3 N
initial velocity (u) = 0 m/sec [ ship was at rest ]
force = mass × acceleration
acceleration = force/mass
a = 5×10∧4 / 3×10∧7 = 5/3 × 10∧-3
distance covered by ship (s) = 3m
∴ by third equation of motion
2as = v² - u²
2 × 5/3 × 10∧-3 × 3 = v² - o²
10 × 10∧-3 = v²
10∧-² = v²
0.1 m/sec = v
so speed attained by the sheep is =0.1 m/sec
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