Question

shiv opens a nut with the help of a spanner of length 30 cm by applying a force of 120 n .calculate the moment of force required to open the nut​

Answer 1

Answer:

9/25

Explanation:

moment of force =F×D=120×30/10000=9/25

Answer 2

Answer:

600Nm

Explanation:

L =30 cm , F= 20N , moment of force =F×D , 30 ×20 = 600Nm