Question

Shiva has two capacitors of variable capacities of range 100$\mu\:F$ to 400 $\mu\:F$ find range of capacitors ​

Answer 1

Explanation:

The negative pin of the cap is usually indicated by a "-" marking, and/or a colored strip along the can. They might also have a longer positive leg. Below are 10µF (left) and a 1mF electrolytic capacitors, each of which has a dash symbol to mark the negative leg, as well as a longer positive leg.

$\huge{\underline {\underline {\mathfrak\green{Badnam}}}}$

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

Solution : We have,

$\implies$ $C_1=100\mu\:F\: and \:C_2 =400\mu\:F$

These produce maximum capacitance when connected in parallel

$\implies\:C_p=C_1+C_2 = 100+400\\\\ \implies\:C_p = 500 \mu\:F$

These produce minimum capacitance when connected in series combination

$\implies \frac{1}{C_s}= \frac{1}{C_1}+\frac{1}{C_2}=\frac{1}{100} +\frac{1}{400}\\\\ \implies\: \frac{1}{C_s}= \frac{4+1}{400}=\sf\cancel\dfrac{5}{400}= \frac{1}{80}\\\\ \implies\:C_s=80 \mu\:F$

So, these capacitors can produce capacity from $80\mu\:F\:to\:500\mu\:F.$