Question

shivam and sanyam together have 25 balls. both lost 4 balls and the product of number of balls they now have is 66 find no. of balls both have initially

Answer 1

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Let the no of ball shivam has initially be x.
Total balls =25

Number of balls shyam has=25-x

After losing four -four balls

Number of balls shivam has=x-4

Number of balls shyam has =25-x-4
=21-x

According to the question

(x-4)(21-x)=66
=>21x-x^2-84+4x=66.
=>-x^2+25x-84-66=0
=>-x^2+25x-150=0
=>-1 (x^2-25x+150)=0
=>x^2-25x+150=0/-1
=>x^2-25x+150=0
=>x^2-(10+15)x+150=0
=>x^2-10x-15x+150=0
=>x (x-10) -15 (x-10)=0
=>(x-15)(x-10)=0............... (1)

=>x-15=0
x=15
So number of balls shivam has initially=15 balls
Number of balls shyam has initially = 25-15
=10 balls


OR
=>x-10=0............... (from (1))
x=10
So number of balls shivam has initially =10 balls
Number of balls shyam has initially =25-10
=15 balls

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