Math, asked by sushmapolker, 2 months ago

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Find the smallest number, which when divided by 16, 24, 32 and 48 leaves remainder 13,
21, 29 and 45 respectively.​

Answers

Answered by prakreetipandey
0

Answer:

The least number is divisible by 16,32,48 and 48 is 480

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