Question

SHM of a particle given by y = 3sinwt + 4 coswt. What is amplitude

Answer 1

Hey

y = x(t) => 'y' is a sinusoidal function of 't'

Let 'm' = wt

--> x(t) = 3 sin m + 4 cos m
= 5 ( 3/5 sin m + 4/5 cos m )
= 5 sin ( m + arctan ( 4/3 ) )
= 5 sin ( wt + arctan ( 4/3 ) )

At 't' = 0 -->
--> x(m) = 5 sin( arctan (4/3) )
= 5 ( 0.8 ) = 4 ✓✓

=> Amplitude of SHM = 4 ✓✓

Hope this helps ^_^

Answer 2

Answer: 5

Explanation: refer to the attachment.