Sho how would you connect three resistors each of reistence 6 ohm so that combinaion has a resistence of (1) 9 ohm (2) 4 ohm
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1) Two in parallel and 1 in series
1/6+1/6=1/r
r=3
total r=3+6=9ohms
2)Two in series and 1 in parallel
1/r=1/12+1/6
=3/12
r=4 ohms
1/6+1/6=1/r
r=3
total r=3+6=9ohms
2)Two in series and 1 in parallel
1/r=1/12+1/6
=3/12
r=4 ohms
Anonymous:
Thanks laksss
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