Question

Shoaib is twice as old as sehzad five years ago his age was three times sehzad age .find their present age.​

Answer 1

Solution :-

Let the Shoaib's age be x

Sehzad's age = 2x

4 years ago,

Shoaib's age = x - 5 years

Sehzad's age = 3(x - 5)

According to the question,

=> 3(x - 5) = 2x - 5

=> 3x - 15 = 2x - 5

=> 3x - 2x = - 5 + 15

=> x = 10

Hence,

Shoaib's age = x = 10 years.

Sehzad's age = 2x = 2 × 10 = 20 years.

Answer 2

Step-by-step explanation:

answer will 999999999

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