Question

. Shoaib is twice as old as Shehzad. Five years ago his age was three times Shehzad's age. Find their
present ages.​

Answer 1

Answer:

10,20

Step-by-step explanation:

Let present age of Shehzad be x years

Thus Sohaib's age = 2x years

Five years ago,

Age of Shehzad= x-5 years

Age of Sohaib= 2x-5 years

Thus, by the problem,

2x-5 = 3*( x-5)

=> 2x-5 = 3x-15

=> 3x-2x= 15-5

=> x= 10 years

Thus present age of Shehzad= 10 years

Sohaib's present age= 2*10= 20 years

Answer 2

this is your answer ok

Step-by-step explanation:

and and this answer is explain