shoaib is twice as old as shehzad .fiveyears ago his age was three times shajad ,s age .find there present age
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let shehzad age be x
shoib age =2x
five yrs ago
x-5 = 3 (2x-5)
x-5= 6x - 15
x-6x = -15 +5
-5x = -10
x =2
shezad age = 2 yrs
shoib age = 4
shoib age =2x
five yrs ago
x-5 = 3 (2x-5)
x-5= 6x - 15
x-6x = -15 +5
-5x = -10
x =2
shezad age = 2 yrs
shoib age = 4
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