Question

Shoba's mothers present age is six times Shoba's present age. Shoba's age 5 years from now will be one
third of their mothers present age ? What are their present ages?

Answer 1

Answer:

5, 30

Step-by-step explanation:

Shoba's age = X

Shoba's mother's present age = 6X

After 5 years,

shoba's age = X + 5

shoba's mother's age = 6X + 5

But, ATQ,

X + 5 = (1/3) * 6X

X + 5 = 2X

X - 2X = -5

-X = -5

X = 5

6X = 30

Answer 2

Given

Shoba's mother age is 6 times of Shoba.

After 5yrs shoba's age will be

$\frac{1}{3}$

of his mothers present age.

To find :- Their present ages

SOLUTION

Let shoba's present age be x

Then shoba's mother age will be 6x

Now,

According to the question,

x + 5

$= \frac{1}{3} (6x)$

We will solve this linear equation in two variable to get the ages of shoba and his mother.

$x \: + \: 5 = \frac{1}{3} (6x)$

$= > x + 5 \: = \: \frac{1}{3} \times 6x$

$= > x + 5 = 2x$

$= > x - 2x = - 5$

$= > - x = - 5$

$= > x = 5$

Hence shoba's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs

VERIFICATION

$x + 5 = \frac{1}{3}(6x)$

$= > 5 + 5 = \frac{1}{3} \times 6 \times 5$

$= > 10 = 2 \times 5$

$10 = 10$

LHS = RHS

Our answer is correct !