Question

Shobha is three years older than his brother Suresh. Six years ago, Shobha's ago was four times the ago of Suresh. Find their present ages.​

Answer 1

Answer:-

Shobha present age = 10 years.

Ramesh present age = 7 years.

Given :-

Shobha age is three years older than his brother.

Six years ago, Shobha 's age was four times the age of suresh.

To find :-

Their present age.

Solution:-

Let the present age of Shobha be x and his brother be y years.

A/Q

• Shobha is 3 years older than his brother.

→$x = y + 3$

Six years ago,

Shobha age was = ( x - 6)

Suresh age was = ( y - 6)

• Shobha age is 4 times the age of suresh.

→$( x-6) = 4(y-6)$

→$x-6 = 4y -24$

→$x-4y = -24 +6$

→$x-4y = -18$

• Put the value of x.

→$y + 3 -4y = -18$

→$-3y +3 = -18$

→$-3y = -18-3$

→$-3y = -21$

→$y = \dfrac{-21}{-3}$

→$y = 7$

hence,

The present age of ramesh is 7 years.

Age of Shobha is :-

→x = y + 3

→x = 7 + 3

→x = 10

hence,

The present age of Shobha is 10 years.

Answer 2

Answer:

Answer:-

Shobha present age = 10 years.

Ramesh present age = 7 years.

Given :-

Shobha age is three years older than his brother.

Six years ago, Shobha 's age was four times the age of suresh.

To find :-

Their present age.

Solution:-

Let the present age of Shobha be x and his brother be y years.

A/Q

Shobha is 3 years older than his brother.

→x = y + 3x=y+3

Six years ago,

Shobha age was = ( x - 6)

Suresh age was = ( y - 6)

Shobha age is 4 times the age of suresh.

→( x-6) = 4(y-6)(x−6)=4(y−6)

→x-6 = 4y -24x−6=4y−24

→x-4y = -24 +6x−4y=−24+6

→x-4y = -18x−4y=−18

Put the value of x.

→y + 3 -4y = -18y+3−4y=−18

→-3y +3 = -18−3y+3=−18

→-3y = -18-3−3y=−18−3

→-3y = -21−3y=−21

→y = \dfrac{-21}{-3}y=

−3

−21

→y = 7y=7

hence,

The present age of ramesh is 7 years.

Age of Shobha is :-

→x = y + 3

→x = 7 + 3

→x = 10

hence,

The present age of Shobha is 10 years.