Math, asked by XxinstaprincessxX, 4 months ago

Shobha's mother's present age is six times Shobha's present age. Shobha's age five years from now will be one third of his mother's present age. What are their present ages?

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Answers

Answered by Anonymous
11

Answer:

Shobo's mother age is 6 times of Shobo. After 5yrs Shobo's age will be 1/3 of his mothers present age. We will solve this linear equation in two Variable to get the ages of Shobo and his mother. Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs

Step-by-step explanation:

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Answered by Anonymous
3

Answer:

The present age of,

Shobha is 5 years

Shobha's mother is 30 years.

Step-by-step explanation:

Let the age of,

Shobha's mother be y years.

Shobha be x years

Shobha's mother's present age is six times Shobha's present age means,

y = 6x ------> eq 1.

Shobha's age five years from now will be one third of his mother's present age means,

x + 5 = ( 1 / 3 ) × y

x + 5 = y / 3

3 ( x + 5 ) = y ------> eq 2.

Substitute eq 1 in eq 2,

6x = 3 ( x + 5 )

x + 5 = 6x / 3

x + 5 = 2x

5 = 2x - x

5 = x

( or )

x = 5 years

Substitute x = 5 in equation 1,

y = 6 × 5

y = 30 years

The present age of,

Shobha ( x years ) is 5 years

Shobha's mother ( y years ) is 30 years.

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