Question

Shobhit is twice as efficient as Rohit and Rohit is twice as efficient as Mohit. If all of them working together and complete the work in 20 days, then find in how many days Rohit and Shobhit working together can complete that work?​

Answer 1

Answer:

23.3 days ( ~ 24 days)

Step-by-step explanation:

$s = 2r$

$r = 2m$

s, r,m being the rate of completing the jobs. (part of the job they can complete in a day independently)

All of them together can complete the job in 20 days, which means they can complete 1/20th part of the job in one day.

$s + r + m = \frac{1}{20}$

$4m + 2m + m \: = \frac{1}{20}$

$m = \frac{1}{140}$

$s + r \: = 2m + 4m = \frac{6}{140}$

Rohit nd Shobhit together finish 6/140th part of the job. hence they can complete the job in 140/6 (23.3 ~ 24 days)