Math, asked by aneriduggar, 9 months ago

Shobo’s mother’s present age is six times Shobo’s present age. Shobo’s age five
years from now will be one third of his mother’s present age. What are their
present ages?

Answers

Answered by jastisridhar1400
4

Answer:

Hi ,

At present,

_________

Shobo's age = x years

His mother's age = 6 times of

Shobo's age

= 6x years

Five years from now

________________

Shobo's age = ( x + 5 ) years

According to the problem given,

x + 5 = one by third of his mother's

present age

x + 5 = 6x / 3

x + 5 = 2x

5 = 2x - x

5 = x

Therefore ,

Shobo's present age = x = 5 years

His mother's age = 6x

= 6 × 5

= 30 years

I hope this helps you.

:)

Answered by Anonymous
3

hey mate here is ur answer :-

let shobos age be x

then her mother's age will be 6x

by 2nd contiditon :-

x+5=2x

x=5yrs

6x=30yrs

so present age of shobo is 5 yrs

and present age of mother is 30 yrs .

hope it helps

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