Question

Shobo's mother's present age is six times Shobo's present age. Shobo's age five years from now will be one-third of his mother's present age. What is their present age?

Answer 1

Step-by-step explanation:

Let the present age of Shobo be 'a' years.

So, his mother's age = 6 times = 6a.

After 5 years, Shobo's age = a + 5

In question, his age will be 1/3 of present age of his mother.

=> (a + 5) = 1/3 * 6a

=> a + 5 = 2a

=> 5 = 2a - a

=> 5 = a

Thus present age of Shobo = 5 year

Age of his mother = 6(5)=30 year

Answer 2

Answer:-

$\red{\bigstar}$ Shobo $\large\leadsto\boxed{\rm\green{5 \: years}}$

$\red{\bigstar}$ Shobo's mother $\large\leadsto\boxed{\rm\green{30 \: years}}$

• Given:-

Shobo's mother's present age is six times of his age.

Shobo's age after five years will be 1/3 rd of his mother's present age.

• To Find:-

The present age of Shobo and his mother.

• Solution:-

Let the present age of Shobo be 'x'.

Likewise, his mother's age will be 6x.

$\pink{\bigstar}$After five years:-

$\dashrightarrow\sf{x + 5 = \dfrac{1}{3} \times 6x}$

$\dashrightarrow\sf{x + 5 = \dfrac{6x}{3}}$

$\dashrightarrow\sf{3(x+5) = 6x}$

$\dashrightarrow\sf{3x + 15 = 6x}$

$\dashrightarrow\sf{6x - 3x = 15}$

$\dashrightarrow\sf{3x = 15}$

$\dashrightarrow\sf{x = \dfrac{15}{3}}$

$\dashrightarrow\boxed{\bf\purple{x = 5}}$

Therefore, their present ages are:-

$\pink{\bigstar}$ Shobo :- 5 years

$\pink{\bigstar}$ Shobo's mother :- 6x = 6 × 5 → 30 years.