Question

Shobo's mother's present age is six times Shobo's present age . Shobo's age 5 years from now will be one third of his mother's present age. What are their present ages.​

Answer 1

Answer:

SOLUTION

Let Shobo's Present age be x

Then Shobo's mother age will be 6x

NOW,

According to the Question,

x + 5 = 1/3 ( 6x )

We will solve this linear equation in two Variable to get the ages of Shobo and his mother.

x + 5 = 1/3 (6x)

=> x + 5 = 1/3 × 6x

=> x + 5 = 2x

=> x - 2x = -5

=> -x = -5

=> x = 5

Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs.

VERIFICATION

x + 5 = 1/3 (6x)

=> 5 + 5 = 1/3 × 6 × 5

=> 10 = 2 × 5

=> 10 = 10

LHS = RHS

Answer 2

Answer:

Shobo's Present age = 5 years

.

Mother's present age = 30 years

.

Step-by-step explanation:

$let \: shobos \: present \: age \: = x \: \: years \\ \\ then \: shobos \: mothers \: present \: age = 6x \: \: years\\ \\ 5 \: years \: later \: shobos \: age = x + 5 \: \: years \\ \\ according \: to \: question \\ \\ x + 5 = \frac{1}{3} \times 6x \\ \\ x + 5 = 2x \\ \\ 5 = 2x - x \\ \\ 5 = x \: \: \: \: or \: \: \: x = 5 \\ \\ shobos \: present \: age = x = 5 \: \: \: years \\ \\ mothers \: age = 6x = 6 \times 5 = 30 \: \: years$

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