Math, asked by Anonymous, 1 month ago

Shobo's mother's present age is six times Shobo's present age . Shobo's age 5 years from now will be one third of his mother's present age. What are their present ages.​ ​


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Answers

Answered by naveenjai2004
1

Step-by-step explanation:

GIVEN :-

Shobo's mother age is 6 times of Shobo.

After 5yrs Shobo's age will be 1/3 of his mothers present age.

TO FIND :- Their present ages

SOLUTION

Let Shobo's Present age be x

Then Shobo's mother age will be 6x

NOW,

According to the Question,

x + 5 = 1/3 ( 6x )

We will solve this linear equation in two Variable to get the ages of Shobo and his mother.

x + 5 = 1/3 (6x)

=> x + 5 = 1/3 × 6x

=> x + 5 = 2x

=> x - 2x = -5

=> -x = -5

=> x = 5

Hence Shobo's present age is 5yrs and present age of mother will be

Hence Shobo's present age is 5yrs and present age of mother will be 5 × 6 = 30yrs.

VERIFICATION

x + 5 = 1/3 (6x)

=> 5 + 5 = 1/3 × 6 × 5

=> 10 = 2 × 5

=> 10 = 10

LHS = RHS

Hope this helps you !!!  

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