Question

Shobo's mother's present age is six times Shobo's present age. Shobo's age five years
from now will be one third of his mother's present age. What are their present ages?​

Answer 1

✬ Shobo's Age = 5 Years ✬

✬ Mother's Age = 30 Years ✬

Step-by-step explanation:

Given:

• Mother's age is 6 times the present age of Shobo.
• After 5 years , Shobo's age will be one third of mother's age.

To Find:

• What are their present ages ?

Solution: Let the present age of Shobo is x years. Therefore,

➙ Mother's age = 6 times of x

➙ Mother's age = 6x years

[ After 5 years ]

• Shobo's age = (x + 5) years

Now , A/q

$\implies{\rm }$ (x + 5) = 1/3 × 6x

$\implies{\rm }$ (x + 5) = 2x

$\implies{\rm }$ 5 = 2x – x

$\implies{\rm }$ 5 = x

So , present age of Shobo is 5 years & present age of Shobo's mother is 6(5) = 30 years.

Answer 2

Given :-

Shobo's mother's present age is six times Shobo's present age. Shobo's age five years  from now will be one third of his mother's present age.

To Find :-

Present ages

Solution :-

Let the age of Shobo be y

And her mother age will be 6y

After 5 years

Age of Shobo = y + 5

ATQ

$\sf y + 5 = \dfrac{1}{3} \times 6y$

$\sf 3(y + 5) = 6x$

$\sf 3y + 15= 6y$

$\sf 15 = 6y-3y$

$\sf 15=3y$

$\sf\dfrac{15}{3} = y$

$\sf 5=y$

Age of Shobo = 5 years

Age of mother = 30 years