Math, asked by sejalnarnoure7a, 1 month ago

Shobo's mother's present age is six times Shobo's present age. Shobo's age five years from now will be one third of his mother's present age What are their present ages?​

Answers

Answered by NikNac08
1

Answer:

let shobo's age be 'x'

mother's age is 6×X = 6x

x+5= 1/3×6x

x+5 = 6x/5

5 = 6x/5-5

5 = 5x-5

5x-5 = 5

5x = 5+5

5x = 10

x = 10/5

x = 5

shobo's age is 5 at present

shobo's mother is = 6×5 = 35

Step-by-step explanation:

hope it helps

Answered by anshumanmano23kvsng
0

Answer:

shobo present age = x

shobo mother present age = 6x

shobo age (after 5 years ) = x+5

shobo mother age (after 5 years )= 6x+5

x+5 = 1/3(6x)

x+5 = 2x

5 = 2x - x

5 = x

x = 5

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