Math, asked by stella9, 1 year ago

shobos mothers present age is six times shobos present age .shobos age five years from now will be one third of his mothers present age . what are their present ages.

Answers

Answered by MonsieurBrainly
54

Let 'x' be Shobo's present age.
Shobo's mother's present age would be 6x.

After 5 years:

x+5=1/3*6x.

We can find Shobo's present age by finding the value of x.

x+5=6x/3.

Transposing /3 from RHS to LHS making it *3:

3(x+5)=6x.
3x+15=6x.

Transposing 3x from LHS to RHS making it -3x:

15=6x-3x.
15=3x.

Transposing *3 from RHS to LHS making is /3:

15/3=x.
5=x.

Therefore the value of x is 5.

Shobo's present age is 5.

His mother's present age is 5x=6(5)=30.





Answered by nikhilnarayanam19
1

Answer:

Let 'x' be Shobo's present age.

Shobo's mother's present age would be 6x.

After 5 years:

x+5=1/3*6x.

We can find Shobo's present age by finding the value of x.

x+5=6x/3.

Transposing /3 from RHS to LHS making it *3:

3(x+5)=6x.

3x+15=6x.

Transposing 3x from LHS to RHS making it -3x:

15=6x-3x.

15=3x.

Transposing *3 from RHS to LHS making is /3:

15/3=x.

5=x.

Therefore the value of x is 5.

Shobo's present age is 5.

His mother's present age is 5x=6(5)=30.

Step-by-step explanation:

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