Question

Shoe that the energy of particle while performing circular motion get conserved?

Answer 1

Explanation:

Angular momentum of a particle performing uniform circular motion

L=Iω

Kinetic energy, K=

2

1

Iω

2

Therefore, L=

ω

2

2K

ω=

ω

2K

L

2

L

1

=

K

2

ω

1

K

1

ω

2

L

2

L

1

=2×2=4

L

2

=

4

L

.