Question

Shopkeeper sold a certain number of toys all at a certain price the number of toys that he sold is a three digit number in which the tens digit and units digit are the same and are non-0 and the price of each toy is a two digit number and express in rupees by mistake we reverse the digits of both the number of items sold and the price of each item in doing so he found that his stock account at the end of the day should 792 items more than what it actually was what is the actual number of toys sold

Answer 1

Step-by-step explanation:

Solution:

Let the number toys be xy. which can be written as 10x+y.

where, y is the digit of units place and x is the digit of tens place.

And price of each toy =ab which can be written as 10a+b.

where, b is the digit of units place and a is the digit of tens place.

Now,

A/q , the shopkeeper has 81 items more than actual.

10x+y=10y+x+81

or, 9x−9y=81

or, x−y=9

The only possible solution of above equation is x=9 and y=0.

So, actual number of toys sold =90

The wrongly recorded number of toys sold =9

∴ Wrongly recorded selling price of a toy =

9

Rs.882

=Rs.98

So, the correct selling price of a toy =Rs.89

Hence, A is the correct answer.

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