Question

Shopkeeper sold a certain number of toys all at a certain price the number of toys that he sold is a three digit number in which the tens digit and units digit are the same and are non-0 and the price of each toy is a two digit number and express in rupees by mistake we reverse the digits of both the number of items sold and the price of each item in doing so he found that his stock account at the end of the day should 792 items more than what it actually was what is the actual number of toys sold​

Answer 1

Answer:

800 toys were sold

Step-by-step explanation:

hope it helped you

Answer 2

Answer:

Answer is 911 toys.

Step-by-step explanation:

Let correct 3 digit number be 100x+10y+z
so the reversed number(incorrect number of toys sold) becomes 100z+10y+x

Since shopkeeper has 792 extra items, that means actual number of toys sold are 792 more than incorrect number of toys sold. i.e: -
100x+10y+z=100z+10y+x+792
Cancelling out 10y from both sides and reshuffling variables and constants we get:
99x-99z=792
x-z=8 or x=8+z --> eq1
Since we know z is non zero, and value of x can be only from 1-9 because it is a digit hence the only possible value of z is 1.
Putting  z =1 in eq 1 we get x=9 and since y=z
Answer is 911.