Math, asked by ayushchaurasiya44, 10 months ago

shopkeeper sold half of the total apples he had and half an apple to his first customer is sold half of remaining apples and half of an apple to his second customer this process he applied to his third fourth and fifth customers now if he is left with 5 apples then find how many apples he had in the beginning ​

Answers

Answered by amitnrw
1

Given : shopkeeper sold half of the total apples he had and half an apple to his first customer and so on to 5 customers . 5 apples left

To find : apples he had in the beginning ​

Solution:

We can do reverse calculation here

After giving to 5th customer he is left with 5 Apples

Apples before giving to 5th Customer = A

=> A  - A/2  - 0.5  = 5

=> A/2  = 5.5

=> A= 11

11 apples before giving to the customer

A  - A/2  - 0.5  = 11

=> A = 23  apples before giving to 4th customer

A  - A/2  - 0.5  = 23

=> A = 47 apples before giving to 3rd customer

A  - A/2  - 0.5  = 47

=> A = 95 apples before giving to 2nd customer

A  - A/2  - 0.5  = 95

=> A = 191 apples before giving to 1st  customer

He had 191 apples in beginning

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