Question

SHORT ANSWER TYPE QUESTIONS
1. Prove that 2+V2 is an irrational number.
2. Write a polynomial from these zeroes 3+V7, 3-V7.
3. Find a Polynomial whose sum of zeroes is 8 and product of zeroes is 12.
4. Find H.C.F of 196 and 3822 from Euclid division algorithm.
5. If one zero of the quadratic polynomial kx2+3x+k is 2 then Find the value of k. ​

Answer 1

Answer:

1. Now, we know that √2 is an irrational number, hence 4√2 is also an irrational number. Therefore, √32 is an irrational number.
2. Now, we know that √2 is an irrational number, hence 4√2 is also an irrational number. Therefore, √32 is an irrational number....
3. Now, we know that √2 is an irrational number, hence 4√2 is also an irrational number. Therefore, √32 is an irrational number....Prove that Root 2 is Irrational Number.
5. Now, we know that √2 is an irrational number, hence 4√2 is also an irrational number. Therefore, √32 is an irrational number....Prove that Root 2 is Irrational Number.1.Prove that Root 2 is Irrational Number3.Prove That Root 2 is Irrational by Long Division Method
7. REFER TO THE ATTACHMENT 1ST
8. Find the Quadratic Polynomial, Sum of Whose Zeroes is 8 and Their Product is 12. Hence, Find the Zeroes of the Polynomial. - Mathematics
10. Find the Quadratic Polynomial, Sum of Whose Zeroes is 8 and Their Product is 12. Hence, Find the Zeroes of the Polynomial. - Mathematics⇒ f ( x ) = x 2 - 8 x + 12.
12. Find the Quadratic Polynomial, Sum of Whose Zeroes is 8 and Their Product is 12. Hence, Find the Zeroes of the Polynomial. - Mathematics⇒ f ( x ) = x 2 - 8 x + 12.Hence, required polynomial.
14. Find the Quadratic Polynomial, Sum of Whose Zeroes is 8 and Their Product is 12. Hence, Find the Zeroes of the Polynomial. - Mathematics⇒ f ( x ) = x 2 - 8 x + 12.Hence, required polynomial.∴ f ( x ) = 0 ⇒ x 2 - 8 x + 12 = 0.
16. Since, the remainder \(98\neq0\), therefore, we divide divisor 196 by remainder 98. Step 2. Since here remainder is zero, therefore, we stop here. Hence \(\text{HCF} (196, 3822)=98\).
17. SORRY GALTI SE ITNA LAMBO HO GAYA LAST QUESTION KA DETA HU EDITING

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.k(2)2+3(2)+k=0

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.k(2)2+3(2)+k=04k+6+k=0

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.k(2)2+3(2)+k=04k+6+k=05k+6=0

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.k(2)2+3(2)+k=04k+6+k=05k+6=0k=−56

Given : 2 is one of zeroes of the polynomial kx2+3x+k, which means x=2 will satisfy it.k(2)2+3(2)+k=04k+6+k=05k+6=0k=−56The value of k is −56

Answer 2

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HERE IS UR ANSWER

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1.refer attachment

2.

${x}^{2} - sx + p$

${x}^{2} - 8x + 12$