Question

Short answer types
- If the length of radius circular field wasincreased by 10%, let us write by calculating
what percent it increase the area circular field​

Answer 1

Step-by-step explanation:

Let the radius of the circle =R therefore area of the circle = [pi][R * R]

Radius of the circle after 10% increase =R+10% of R=R+R/10=11R/10

Therefore AREA of the circle with radius 11R/10 =[pi][11R/10*11R/10]=[pi][121R*R/100] Hence INCREASE in the AREA of the circle=[pi][121R*R/100]-[pi][R*R] =[pi] [R*R][121/100-1] =[pi][R*R][121-100]/100=[pi][R*R][21]/100 THEREFORE % increase in the area of the circle=[pi][R

*R][21/100]/[pi][R*R] whole multiplied by 100=21 HENCE increase in the area of the circle =21% NOTE : pi is a constant whose value=22/

OR

21%.

21%.A=(pie)(r*r)

21%.A=(pie)(r*r)Radius increased by 10%:

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)A'=(pie)(r*r)(1.21)

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)A'=(pie)(r*r)(1.21)=1.21*A

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)A'=(pie)(r*r)(1.21)=1.21*A=(1 + 0.21)*A

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)A'=(pie)(r*r)(1.21)=1.21*A=(1 + 0.21)*A=A + (0.21)*A

21%.A=(pie)(r*r)Radius increased by 10%:A'=(pie)(1.1*1.1)(r*r)A'=(pie)(r*r)(1.21)=1.21*A=(1 + 0.21)*A=A + (0.21)*ATherefore, Area increase by 21% when radius is increased by 10%.