Physics, asked by Kuyung8509, 1 year ago

Short bar magnet is placed with its n polepointing south

Answers

Answered by Anonymous
0

Solution :

Here, d=10cm=0⋅1m, H=0⋅4gauss=0⋅4×10−4T, M=?

Neutral points in this case, lie on axial line of magnet, such that μ04π2Md3=H

∴10−7×2M(0⋅1)3=0⋅4×10−4 or

Similar questions