Short bar magnet is placed with its n polepointing south
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Solution :
Here, d=10cm=0⋅1m, H=0⋅4gauss=0⋅4×10−4T, M=?
Neutral points in this case, lie on axial line of magnet, such that μ04π2Md3=H
∴10−7×2M(0⋅1)3=0⋅4×10−4 or
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