Question

SHORT QUESTION
If x + y =12 and xy =32, Find the value of
x² + y^2
​

Answer 1

Answer:

144=x^2+y^2+2xy

144-64=x^2+y^2

80

Answer 2

Step-by-step explanation:

x+y=12

xy=32

so y=12-x

x(12-x)=32

12x-x^2=32

x^2-12x-32=0

x^2-8x+4x-32=0

x(x-8) +4(x-8) =0

(x-8) (x+8)=0

x=8 or x=-4

8^2+-4^2

64+16

=80

btw thanks for marking me brainliest