Question

Shortest bond length of oxygen molecule

Answer 1

Explanation:

The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length.

so, we know how to calculate the bond order….actually let me just show it

(B.O)=1/2[(no of electron in anti bonding MO)-(no.of electrons in bonding MO)]

for, O2 : BO=1/2[10–6]=2

for, O2- : BO=1/2[10–7]=1.5

for, O2+ : BO=1/2[10–5]=2.5

for, O2^–2 : BO=1/2[10–8]=1

for, O2^+2 :BO=[same as N2]=3

So, the increasing sequence bond order

O2^-2 < O2- < O2 < O2+ < O2^+2

therefore, the increasing order of bond length of these species is,

O2^+2 < O2+ < O2 < O2 < O2^-2