shortest distance between two octahedral voids in hcp unit is
Answers
Answered by
5
Answer: Shortest distance between two octahedral voids in hcp unit is edge length /√2.
Explanation:
Total of 4 octahedral voids are present in the closed packing structure of the cubic. One is present at the centre of the cube and rest of the others at the edge centres. To calculate the minimum distance, measure the distance between two adjacent edge centres.
Similar questions